16x=5x^2

Solution for 16x=5x^2 equation:

16x=5x^2

We move all terms to the left:

16x-(5x^2)=0

determiningTheFunctionDomain
-5x^2+16x=0

a = -5; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-5)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-5}=\frac{-32}{-10}
=3+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-5}=\frac{0}{-10}
=0
$